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Answer (1 of 2) Making this equation in the form y = f(x) is tough way to solve the problem According to me, it is better to differentiate the whole equation wrtFind the critical points of the function {eq}f(x,y) = 4 x^3 y^3 3xy {/eq} and classify them as local maximum or minimum or saddle pointsCalculus Find dy/dx x^3y^3=3x^2y3xy^2 x3 − y3 = 3x2y − 3xy2 x 3 y 3 = 3 x 2 y 3 x y 2 Differentiate both sides of the equation d dx (x3 −y3) = d dx (3x2y−3xy2) d d x ( x 3 y 3) = d d x ( 3 x 2 y 3 x y 2) Differentiate the left side of the equation Tap for more steps Differentiate
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Extended Keyboard Examples Upload Random Compute answers using Wolfram's breakthrough technology & knowledgebase, relied on by millions of students & professionals For math, science, nutrition, history, geography, engineering, mathematics, linguistics, sports, finance, music WolframAlpha brings expertlevel knowledge We have (x3 y3) = 3xy2 dy dx We can rearrange this Differential Equation as follows 3 dy dx = x3 y3 xy2 = x3 xy2 y3 xy2 = x2 y2 y x = ( x y)2 y x This would lead us to try a substitution, Let v = y x ⇒ y = vx Factorize x(x^3y^3) 3xy (xy) ← Prev Question Next Question → 0 votes 277 views asked in Mathematics by Sonu khan (356k points) Factorize x(x 3y 3) 3xy (xy) factorisation of algebraic expressions;
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